log^2(3x-7)=3

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Solution for log^2(3x-7)=3 equation: 


Simplifying
log2(3x + -7) = 3

Reorder the terms:
g2lo(-7 + 3x) = 3
(-7 * g2lo + 3x * g2lo) = 3
(-7g2lo + 3g2lox) = 3

Solving
-7g2lo + 3g2lox = 3

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-3 + -7g2lo + 3g2lox = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + -7g2lo + 3g2lox = 0

The solution to this equation could not be determined.

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